0=96x^2-56x-96

Solution for 0=96x^2-56x-96 equation:

0=96x^2-56x-96

We move all terms to the left:

0-(96x^2-56x-96)=0

We add all the numbers together, and all the variables

-(96x^2-56x-96)=0

We get rid of parentheses

-96x^2+56x+96=0

a = -96; b = 56; c = +96;
Δ = b2-4ac
Δ = 562-4·(-96)·96
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-200}{2*-96}=\frac{-256}{-192}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+200}{2*-96}=\frac{144}{-192}
=-3/4
$